Gold Member Username: BlainewPost Number: 2810 Registered: Nov-05 | okay here is the deal. dy/dx simply means take the derivative with respect to x. so when you dont have an x variable, you take the derivative AS IF the variable was x. but then you multiply that derivative by dy/dx, and dy/dx simply becomes the variable you solve for ex. x^2+y^2=7 you want the derivative (dy/dx) of the whole thing dy/dx = ???? step 1- take the regular derivative of x^2 =2x Step 2 - take the derivative of y^2, but since it is not x you have to do this 2y times dy/dx step 3 - derivative of 7 =0 put it all together and you get this 2x+2y*dy/dx = 0 now remember what we were trying to find...dy/dx of the whole problem......dy/dx is just like a variable you can solve for..so just use algebra 2x+2y*(dy/dx) = 0 2y*(dy/dx)=-2x dy/dx = -2x/2y dy/dx = -x/y |
Gold Member Username: JtownTeam Revolution, Texas Post Number: 1717 Registered: Mar-07 | oh, forgot about the constant, plus I didn't know you were taking the derivative like that..... sh1t, now that I see it, d@mn I feel stupid cause it was so easy |
Gold Member Username: BlainewPost Number: 2814 Registered: Nov-05 | ya....i mean it seems hard to explain..but when you know it..its simple |
Silver Member Username: MendonmafiaUSA Post Number: 684 Registered: Aug-06 | wow i deffinately should have known that, thats so simple. maybe i should hit the books. |
Gold Member Username: JtownTeam Revolution, Texas Post Number: 1734 Registered: Mar-07 | well I'm done with math anyway, on to Physics.... |
Silver Member Username: MendonmafiaUSA Post Number: 685 Registered: Aug-06 | im done with my physics and math on to being an engineer im too young for this hahaha |
Gold Member Username: BlainewPost Number: 2818 Registered: Nov-05 | mark how old are you? |
Silver Member Username: MendonmafiaUSA Post Number: 687 Registered: Aug-06 | 18 and a junior in college hahaha. i guess you could say im advanced LOL. |
Gold Member Username: BlainewPost Number: 2827 Registered: Nov-05 | whoa..niceee |