PVC port displacement??

TJ Silver Member Username: Thomas_g NM Post Number: 806 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 04:27 GMT Sup i wuz wondering, in u have say 2 cuft volume inside an enclosure and thats the airspace u need for a sub and u wanna add a port, the port takes space also right so that will bring down the volume of airspace inside, so how do u figure how much space a PVC port takes up inside an enclosure?? Thanx peeps.
TJ Silver Member Username: Thomas_g NM Post Number: 808 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 05:26 GMT anyone??
marshall white Gold Member Username: Southernrebel Monroe, Louisiana USA Post Number: 2975 Registered: Mar-04	Posted on Tuesday, May 30, 2006 - 05:53 GMT pi * radius^2 * port length = port displacment you have to factor this displacment into you box caluculations...you tune a box based on 'net' volume, not 'gross'
TJ Silver Member Username: Thomas_g NM Post Number: 811 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 06:04 GMT Repeat plez for a dumbazz. Ima 16 year old flunkin math.lol. Thanx marshall.
TJ Silver Member Username: Thomas_g NM Post Number: 812 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 06:13 GMT Say if im making a ported enclosure 2cuft of inner volume, it would be these dimentions if i use 3/4in mdf:w=20 h=16.5 d=14, right? If i add a 3" wide and 9.9544" long PVC port, what would be left of my inner volume?? Thanx.
TJ Silver Member Username: Thomas_g NM Post Number: 813 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 06:15 GMT Help me plezzz!!!
\|\/\|aTT \|F Silver Member Username: Matt12490 Benicia, California USA Post Number: 978 Registered: May-05	Posted on Tuesday, May 30, 2006 - 07:50 GMT i got a port displacement of 0.04 cu. ft.
WrEaK HaVoC(.'~DAYE£?~'.) Gold Member Username: 54danny54 Betsy layne, Kentucky..GO... USA duh Post Number: 2479 Registered: Nov-04	Posted on Tuesday, May 30, 2006 - 10:45 GMT TJ...u know P.E.M.D.A.S? 3.14(1.51.5)*port 9.9544
TJ Silver Member Username: Thomas_g NM Post Number: 834 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 16:12 GMT P E M D A S?? Ok i know pie= 3.14 so its 3.14x(1.5x1.5)x 9.9544 Whered u get 1.5 from? Did u get it from half of the ports width?? Will 3.14x(1.5x1.5)x9.9544 give me the cuft??Thanx guyz.
TJ Silver Member Username: Thomas_g NM Post Number: 841 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 16:35 GMT so pie x radius(squared) x port length = my port displacement in what? CUFT? Thanx guyz.
marshall white Gold Member Username: Southernrebel Monroe, Louisiana USA Post Number: 2977 Registered: Mar-04	Posted on Tuesday, May 30, 2006 - 21:37 GMT TJ, it would be: 3.14 x (1.5^2) x 9.95 = 70.297 cu inches 70.297 / 1728 = ~.04 cu ft i'm guessing this box is for either 1 10" or 1 12"...so i'm goint to estimate 0.06cuft for sub displacment. that will make your box ~1.9cuft net tuned to ~29hz. ps... w/ a 12.75" long 4" port the box will be 1.85cuft net tuned to 34hz.
TJ Silver Member Username: Thomas_g NM Post Number: 864 Registered: Oct-05	Posted on Tuesday, May 30, 2006 - 21:41 GMT Thank you very much marshall, so the port displacement doesnt make much of a difference right??

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