New member Username: Dubz_on_my_jeepPost Number: 2 Registered: Oct-05 | I have been looking at amps and the power acoustic 980 watt amp looked decent. I didn't know if i should go with that or a Pioneer 760 watt. I didn't know if any body has had any experience with the power accoustic. The amp will be hooked up to either 2 kicker comp vr's or 1 or 2 JL w1 13 Also which setup is better the comp vr's or the Jl's |
Gold Member Username: Basshead86Ocala, FL USA Post Number: 2505 Registered: Aug-05 | i would choose the JL's personally. i would also look into maybe getting a kicker amp. i'm not too fond of Pioneer or PA amps. kickers are excellent amps for the money. |
New member Username: Dubz_on_my_jeepPost Number: 4 Registered: Oct-05 | To push the 1 or 2 JL W1's what kind of kicker amp would i need...and how much would it cost. Because i dont want to spend over 700 bucks (give or take a little bit)?? |
New member Username: Dubz_on_my_jeepPost Number: 6 Registered: Oct-05 | To push the 1 or 2 JL W1's what kind of kicker amp would i need. And how much will it cost? I am only looking at spending around 700 bucks total on everything (Give or take a Little) |
Bronze Member Username: Wolf_houndPost Number: 67 Registered: Sep-05 | whats the rms on the w1 yeah stay away from power craptastic, pioneer i dont know havent had experience with them. |
Gold Member Username: RovinTrinidad & T... Post Number: 1560 Registered: Jul-05 | Lucas - Are u sure u know prices ? a single 13w7 = $700 ! Also do not put cheaper amps of good subs , u can do vice versa though.... for $700 u can get 2 12" comp vrs or Alpine 12" type R & a good Orion 1200 amp & a prefab box if u can't build 1 yourself ..... |
Silver Member Username: FandimReno, Nevada United State... Post Number: 349 Registered: Jun-05 | He said a W1 13. Not a 13W7. :-P |
Gold Member Username: RovinTrinidad & T... Post Number: 1573 Registered: Jul-05 | oh crap - when i saw "JL w1 13" , my mind was thinking 13w7 ...lol so its this then - http://mobile.jlaudio.com/products_subs.php?series_id=17 then that would be 1/2 the power of a current model compvr . |